(a) Determine the formula of an ionic solid in which the cation \(P^{+}\) are present at alternate corners of the cube and anion \(Q^{-}\) are present at alternate face centers.

Determine the simplest formula of an ionic compound in which cations are present at the corner and the anions occurs at the centre of each face.

What is the formula of the crystalline compound in which the atoms A are present at all the eight corners and atoms B at the centres of all the six faces ?

A compound formed by elements A and B crystallises in a cubic structure where A atoms are present at the corners of a cube and the B atoms are present at the face centres.The formula of the compound is

Find the lowest possible empirical formular in an arrangements of unit cell where A atoms are present at corners and alternate face centers, B atoms are present at alternate edge centers and C atoms are present at half of the mid of line joining opposite face centers. Assume: Any atom present in the inner location of the unit cell should be considered completely within the unit cell structure.

Find the molecular formula of a compound made by atoms A and B, where A atoms present at all corners of cubic lattice and B atoms at alternate face centre.

A compound is made up of two elements X and Y and crystallizes in bcc structure. Atoms of X are present at the corners of the cube. Atoms of Y are present at the centre of the cube. The formula of the compound is

An ionic compound is made up of cations A and anions B . if cations A are at the alternate corners and anions are at the alternate faces of the cubic unit cell then empirical formula of the compound will be

A cubic solid is made up of two elements P and Q . Atoms of P are present at the corners of the cube and atoms of Q are present at body centre. What is the formula of the compound and what are coordination numbers of P and Q ?