If `alpha,beta` and `gamma` are the values of x,y and z respectively which satisfy the system of equations 2x+y+z=1,x-2y-3z=1 and 3x+2y+4z=5, then `sin^(-1)((alpha)/(gamma))=`

The solution of the system of equations is x-y+2z=1,2y-3z=1 and 3x-2y+4y=2 is

For the system of equations 3x+y=1,x-2y=5 and x-y+3z+3=0, the value of z is

By crammer's rule ,if the values of x,y and z which satisfy the system of equations x+y+z=2, x+2y+3z=1 ,and 3x+y-5z=4 are respectively L,M and N, then 3L+5M+N=

By crammer's rule,if the values of x,y and z which satisfy the system of equations x+y+z=2 ,x+2y+3z=1 ,and 3x+y-5z=4 are respectively L,M and N then 3L +5M+N=

For the system of equation 3x + y =1, x - 2y =5 and x-y + 3z +3 =0 , the value of z is

Let x,y,z in R^(+) and 2xy+3yz+4xz=18 . If alpha , beta and gamma be the values of x , y and z respectively, for which xyz attains its maximum value, then the value of 2alpha+beta+gamma=

The system of lienar equations x-y+z=1 x+y-z=3 x-4y+4z=alpha has