A block of mass `5 kg` is initially at rest on a rough horizontal surface. A force of `45 N` acts over a distance of `2 m`. The force of friction acting on the block is `25 N`. The final kinetic energy of the block is

A block of mass 4 kg is initially at rest on a horizontal frixtionless surface. A horizontal force vec(F) = (3+x) hat(i) newtons acts on it, when the block is at x = 0 . The maximum kinetic energy of the block between x = 0 and x = 2 m is

A block of mass 2 kg, initially at rest on a horizontal floor, is now acted upon by a horizontal force of 10 N . The coefficient of friction between the block and the floor is 0.2. If g = 10 m//s^(2) , then :

A block of mass m is placed on a rough horizontal surface. If minimum force to pull the block is (mg)/(2) then coefficient of friction is :

A 20 kg block is initially at rest on a rough horizontal surface. A horizontal force of 75 N is required to set the block in motion. After it is in motion, a horizontal force of 60 N is required to keep the block moving with constant speed. The coefficient of static friction is

A 10 kg block is initially at rest on a rough horizontal surface. A horizontal force of 60 N is required to set the block in motion . After it is in motion , a horizontal force of 50 N is required to keep the block moving with constant velocity . The ratio coefficient of static and kinetic friction is

A block of mass 4 kg is initially at rest on a horizontal frictionless surface. A force vec(F) = (2x+3x^(2))hat(i) N acts horizontally on it. The maximum kinetic energy of the block between x = 2m and x=4m in joules is

A block of mass 1 kg in kept on a rough horizontal surface with mu_(s)=0.1 . A force of 0.5 N is applied as shown in the figure. What is the frictional force applied by ground on the block?

A block of mass 5 kg is at rest on a rough inclined surface. If angle of inclination of plane is 60^(@) , then force applied by it on block is

A block of mass 5kg is resting on a rough surface as shown in the figure. It is acted upon by a force of F towards right. Find frictional force acting on block when 25N.

A 2.5 kg block is initially at rest on a horizontal surface. A horizontal force vecF of magnitude 6.0 N and a vertical force vecP are then applied to the block (Fig. 6-31). The coefficients of friction for the block and surface are mu = 0.40 and mu = 0.25 . Determine the magnitude of the frictional force acting on the block if the magnitude of vecP is (a) 8.0 N. (b) 10 N, and (c) 12 N