A body of mass 4kg is projected vertically up with a velocity of `20ms^(-1)` . If the energy spent in overcoming air resistance is 200J ,the maximum height attained by it is? (g=10m/`s^(2)`)

A body is projected at 45^(@) with a velocity of 20ms^(-1) has a range of 30m .The decrease in range due to air resistance is? (g=10ms^(-2))

A body is projected vertically up with a speed of 20ms^(-1) .The distance travelled by it in "3" seconds it (g=10ms^(-2))

A ball is projected vertically up wards with a velocity of 100 m/s. Find the speed of the ball at half the maximum height. (g=10 m//s^(2))

A body of mass 2kg is projected vertically upwards with a speed of 3m//s . The maximum gravitational potential energy of the body is :

A body of mass 2kg is projected vertically up with velocity 5ms^(-1) . The work done on the body by gravitational force before it is brought to rest momentarily is

A ball is projected vertically up with speed 20 m/s. Take g=10m//s^(2)

A stone is projected vertically upwards.When it reaches half the maximum height,its velocity is 20m/s.What is the maximum height attained by the stone? (g=10m/s^(2)

A particle of mass 2 kg is projected vertically upward with a velocity of 20 m/s . It attains maximum height of 17 m. The loss in mechanical energy due to air drag is (g = 10 ms^-2 )

A body projected at 45^(@) with a velocity of "20m/s" has a range of 10m.The decrease in range due to air resistance is g=10ms^(-2)

A ball is thrown vertically upwards with a velocity of 10 ms^(-1) . It returns to the ground with a velocity of 9 ms^(-1) . If g=9.8 ms^(-2) , then the maximum height attained by the ball is nearly (assume air resistance to be uniform)