Home
Class 12
MATHS
Consider the number n=2^(2).3^(3).5^(5)....

Consider the number `n=2^(2).3^(3).5^(5).7^(4).11^(3)`. Then the number of divisors of n that are perfect cubes are

Promotional Banner

Similar Questions

Explore conceptually related problems

Consider N=3^(3)*4^(3)*6^(3), then the number of divisors of N, which are perfect cubes,is

If M=2^(2)xx3^(5),N=2^(3)xx3^(4) , then the number of factors of N that are common with factors of M is

If N=2^(3)times3^(5)times5^(7) then number of divisors of N which are not divisible by 30 is

Consider the natural number n=453600. Statement-1: The number of divisors of n is 180. Statement-2: The sum of the divisors of n is ((2^(6)-1)(3^(5)-1)(5^(3)-1)(7^(2)-1))/(48)

If N=12^(3)xx3^(4)xx5^(2) , then the total number of even factors of N is

Consider N=2^(2)3^(2)4^(2)6^(2)5^(2) and give the answers of the following questions . (i) Find the total number of divisible of N . (ii) Find the total number of divisors divisible by 24 (iii) Find the total number of divisors divisible by 5. (iv) Find the total number of divisors which are perfect square. (v) Find the number of divisors which are perfect cube.

Sum of perfect square divisors of 2^(3)xx21^(2)xx91^(1) is A,then number of divisors of A is

The number of divisors of 2^(4).3^(3).5^(2), having two prime factors,is

Consider a number n=21 P 5 3 Q 4. The number of values of Q so that the number 'N' is divisible by 8, is