Two second after projection, a projectile is moving at `30^(@)` above the hoorizontal, after one more second it is moving horizontally. The intialy speed of the projectile is `(g = 10 m//s ^(2))`

Two seconds after projection, a projectile is travelling in a direction inclined at 30^(@) to the horizon. After one more second it is travelling horizontally. Then

Choose the correct option Two seconds after the projection, a projectile is moving at 30^(@) above the horizontal, after one more second it moves horizontally (g = 10 m//s^(2)) .

Two second after projection, a projectile is travelling in a direction inclined at 30^(@) to the horizontal. After one more second, it is travelling horizontally. Find the magnitude and direction of the velocity of projection.

Two seconds after projection, a projectile is travelling in a direction inclined at 30^@ to the horizontal. After one more second, it is travelling horizontally. Find the magnitude and direction of its velocity.

After one second the velocity of a projectile makes an angle of 45^(@) with the horizontal. After another one more second its is travelling horizontally. The magnitude of its initial velocity and angle of projectile are (g=10m//s^(2))

One second after the projection, a stone moves at an angle of 45@ with the horzontal. Two seconds from the start, it is travelling horizontally. Find the angle of projection with the horizontal. (g=10 ms^(-2)) .

From the ground, a projectile is fired at an angle of 60 degree to the horizontal with a speed of 20" m s"^(-1) The horizontal range of the projectile is

A projectile is thrown with velocity u making an angle theta with the horizontal. Its time of flight on the horizontal ground is 4 second. The projectile is moving at angle of 45^(@) with the horizontal just one second after the projection. Hence the angle theta is (take g=10m//s^(2) )