The vector bar(c) is perpendicular to b...

The vector `bar(c)` is perpendicular to both `bar(a)=(bar(i)-2bar(j)+bar(k)),bar(b)=(2bar(i)+bar(j)-bar(k)),bar(c)` also satisfies ,`|bar(c)times(bar(i)-bar(j)+bar(k))|=2sqrt(6)` then `bar(c)=`

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