Tripositive ion of an element has 13 protons and 14 neutrons . Calculate the of number of electrons present in K and M shells of the neutral atom.

Options

A. 2
B. 1
C. 3
D. 5

Explanation

To solve the problem step by step, we need to follow these instructions:

### Step 1: Determine the Atomic Number
The atomic number of an element is equal to the number of protons. In this case, the element has 13 protons. Therefore, the atomic number is 13.

### Step 2: Identify the Neutral Atom's Electron Count
In a neutral atom, the number of protons is equal to the number of electrons. Since the element has 13 protons, it also has 13 electrons when it is neutral.

### Step 3: Determine the Electron Configuration
The electron configuration of an atom describes how the electrons are distributed in the various energy levels (shells). The maximum number of electrons that can occupy each shell is given by the formula 2n², where n is the shell level:
- K shell (n=1): can hold 2 electrons
- L shell (n=2): can hold 8 electrons
- M shell (n=3): can hold 18 electrons

For the neutral atom with 13 electrons, the distribution will be:
- K shell: 2 electrons
- L shell: 8 electrons
- M shell: 3 electrons

### Step 4: Analyze the Tripositive Ion
A tripositive ion (M³⁺) means that the atom has lost 3 electrons. Therefore, we need to subtract 3 electrons from the neutral atom's total:
- Neutral atom: 13 electrons
- Tripositive ion: 13 - 3 = 10 electrons

### Step 5: Redistribute Electrons in the Shells for the Ion
Now we need to redistribute the remaining 10 electrons:
- K shell: 2 electrons (remains the same)
- L shell: 8 electrons (remains the same)
- M shell: 0 electrons (since we have only 10 electrons total)

### Step 6: Conclusion
Now, we can summarize the number of electrons in the K and M shells of the neutral atom:
- K shell: 2 electrons
- M shell: 0 electrons (after losing 3 electrons)

### Final Answer
- Number of electrons in K shell: 2
- Number of electrons in M shell: 0