`6=z+2`

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Find the distance of the point (-6,0,0) from the plane 2x-3y+6z = 2 .

Find the distance of the point (-6, 0, 0) from the plane 2x - 3y + 6z = 2.

By how much is 2x - 3y + 4z greater than 2x + 5y - 6z + 2?

If z = i(i + sqrt(2)) , then value of z^(4) + 4z^(3) + 6z^(2) + 4z is

Simplify : (Use formulae) (4x-5y+6z)^2+(4x+5y-6z)^2

Find the greatest value of |z| when |z-(6)/(z)|=2,z being a complex number.

If z=3-2i then show that z^(2)-6z+13=0 Hence find the value of z^(4)-4z^(3)+6z^(2)-4z+17

Factories: 9 + 6z + z^(2)

Factorise the expressions and divide them as directed : 4yz(z^2 + 6z – 16) -: 2y(z + 8)