Factorize the following `|3a+b+c a^3+b^3+c^3a+b+c a^2+b^2+c^2a^4+b^4+c^4a^2+b^2+c^2a^3+b^3+c^3a^5+b^5+c^5|`

Factorize the following |[3,a+b+c,a^3+b^3+c^3],[a+b+c,a^2+b^2+c^2,a^4+b^4+c^4],[a^2+b^2+c^2,a^3+b^3+c^3,a^5+b^5+c^5]|

Factorize the following |[3,a+b+c,a^3+b^3+c^3],[a+b+c,a^2+b^2+c^2,a^4+b^4+c^4],[a^2+b^2+c^2,a^3+b^3+c^3,a^5+b^5+c^5]|

Factorize the following 3,a+b+c,a^(3)+b^(3)+c^(3)a+b+c,a^(2)+b^(2)+c^(2),a^(4)+b^(4)+c^(4)a^(2)+b^(2)+c^(2),a^(3)+b^(3)+c^(3),a^(5)+b^(5)+c^(5)]|

Factorise : 2ab^(2) c - 2a + 3b^(3) c - 3b - 4b^(2) c^(2) + 4c

Add: 3a - 4b + 4c, 2a + 3b - 8c, a - 6b + c

Simplify the following:(a-2b+5c) (a-b)-(a-b-c) (2a + 3c) + (6a + b) (2c-3a-5b)

Add the following algebraic expressions : 2a - 3b + 4c , -3a + 2b - 5c , 7a - c and 3b + 6c

Simplify the following : (a+2b+3c)(a+b)-(a-b-c)(2a+3c)+(2a+b)(2c-2a-4b)

Prove that : a^3+b^3+c^3-3a b c=1/2(a+b+c)"{"a-b")"^2+(b-c)^2+(c-a)^2}