`50 mL` of `0.1M` solution of a salt reacted with `25 mL` of `0.1M` solution of sodium sulphite. The half reaction for the oxidation of sulphate ion is:
`SO_(3(aq.))^(2-)+H_(2)O_((l))rarrSO_(4(aq.))^(2-)+2H_(+(aq.))+2e`
If the oxidation number of metal in the salt was `3`, what would be the new oxidation number of metal?

In an experiment 50ml of 0.1(M) solution of a salt is reacted with 25ml of 0.1(M) solution of sodium sulphite. The half equation for the oxidation of sulphite ion is SO_(3)^(2-)(aq)+H_(2)O rarr SO_(4)^(2-)(aq)+2H^(+)(aq)+2e^(-) If the oxidation number of metal in the salt was 3 , what would be the new oxidation number of metal?

50 mL of 0.1 M solution of a salt reacted with 25 mL of 0.1 M solution of sodium sulphite. The half reaction for the oxidation of sulphite ion is: SO_(3)^(2-)(aq)+H_(2)O(l) rarr (aq)+2H^(+)(aq)+2e^(-) If the oxidation number of metal in the salt was 3 , what would be the new oxidation number of metal:

50 mL of 0.1 M solution of a salt reacted with 25 mL of 0.1 M solution of sodium sulphite. The half reaction for the oxidation of sulphite ion is: SO_(3)^(2-)(aq)+H_(2)O(l) rarr (aq)+2H^(+)(aq)+2e^(-) If the oxidation number of metal in the salt was 3 , what would be the new oxidation number of metal:

In an experiment, 50 ml of 0.1 M solution of a salt reacted with 25 ml of 0.1 M solution of sodium sulphite. The half equation for the oxidation of sulphite ion : SO_(3(aq))H_2OrarrSO_(4(aq))^(2-)+2H_((aq))^+ If the oxidation number of the metal in the salt was 3, what would be the new oxidation number of the metal ?

In an experiment, 50 mL of 0.1 M solution off a metallic salt M(NO_(3)) reacted exactly with 25 mL of 0.1 M solution of NaSO_(3) in the reaction SO_(3)^(2-) is oxidized to SO_(4)^(2-) . If in the original salt oxidation number of the metal was 3, what would be the new oxidation number of metal?

In an experiment, 50 mL of 0.1 M solution off a metallic salt M(NO_(3)) reacted exactly with 25 mL of 0.1 M solution of NaSO_(3) in the reaction SO_(3)^(2-) is oxidized to SO_(4)^(2-) . If in the original salt oxidation number fo the metal was 3, what would be the new oxidation number of metal?

20 ml of 0.1 M solution of metal ion reacted with 20 ml to 0.1 M SO_(2) solution . SO_(2) reacted according to the equation SO_(2) + 2H_(2)O rarr SO_(4)^(2-) + 4H^(+) + 2e^(-) . If the oxidation no. of metal ion was + 3 , the new oxidation number of the metal would be :

Among the reactions given the oxidant and the reductant in each case: H_(2)S(g)+HNO_(3)(aq)toH_(2)SO_(4)(aq)+NO_(2)(g)H_(2)O(l)