Surface mass density of disc of mass `m` and radius `R` is `alpha-Kr^(2)`. Then its moment of inertia `w.r.t.` axis of rotation passing through center and perpendicular to the plane of disc is :

Surface mass density of disc of mass m and radius R is Kr^(2) . Then its moment of inertia w.r.t. axis of rotation passing through center and perpendicular to the plane of disc is :

A disc of mass m and radius R has a concentric hole of radius r . Its moment of inertia about an axis through its center and perpendicular to its plane is

A disc of mass m and radius R has a concentric hole of radius r . Its moment of inertia about an axis through its center and perpendicular to its plane is

Calculate the moment of inertia of a disc of radius R and mass M, about an axis passing through its centre and perpendicular to the plane.

Four similar point masses (m each) are symmetrically placed on the circumference of a disc of mass M and radius R. Moment of inertia of the system about an axis passing through centre O and perpendicular to the plane of the disc will be

A disc of radius R has a concentric hole of radius R /2 and its mass is M. Its moment of inertia about an axis through its centre and perpendicular to its plane, is

A disc of radius R has a concentric hole of radius R /2 and its mass is M. Its moment of inertia about an axis through its centre and perpendicular to its plane, is