If linear charge density of a wire of length L depends on distance x from one end as `lambda=(lambda_(0)(x))/(L` .Find total charge of wire :-

If linear charge density of a wire as shown in the figure is lambda

the linear charge density of a thin metallic rod varies with the distance x from the end as lambda=lambda_(0)x^(2)(0 le x lel) The total charge on the rod is

the linear charge density of a thin metallic rod varies with the distance x from the end as lambda=lambda_(0)x^(2)(0 le x lel) The total charge on the rod is

The linear mass density of a rod of length 2L varies with distance (x) from center as lambda=lambda_(0)(1+(x)/(L)) .The distance of COM from center is nL.Then n is

[" A wire of length "L" is placed along "x" &axis "],[" with one end at the origin.The linear charge "],[" density of the wire varies with "],[" Q."" distance "x" from the origin as "lambda=lambda_(0)((x^(3))/(L))" ."],[" Where "varnothing_(0)" is a positive constant.The total "],[" charge "Q" on the rod is "]

A semicircular wire is uniformly charged with linear charge density dependent on the angle theta from y -direction as lambda=lambda_(0) |sin theta| , where lambda_(0) is a constant. The electric field intensity at the centre of the arc is

The linear charge density of a uniform semicircular wire varies with theta shown in the figure as lambda=lambda_(0)costheta if R is the radius of the loop ,of the charge on the wire is