In an equilateral `Delta ABC, D ` is the midpoint of AB and E is the midpoint of AC. Then, `ar (Delta ABC) : ar (Delta ADE)=?`

In an equilateral triangle ABC , D is the mid-point of AB and E is the mid-point of AC. Find the ratio between ar ( triangleABC ) : ar(triangleADE)

D is the mid-point of side BC of Delta ABC and E is the mid-point of BO. If O is the mid-point of AE, then ar( Delta BOE) = 1/k ar( Delta ABC). Then k equals

In triangle ABC,D is the midpoint of AB, E is the midpoint of DB and F is the midpoint of BC. If the area of DeltaABC is 96, the area of DeltaAEF is

In triangle ABC,D is the midpoint of AB, E is the midpoint of DB and F is the midpoint of BC. If the area of DeltaABC is 96, the area of DeltaAEF is

In triangle ABC,D is the midpoint of AB, E is the midpoint of DB and F is the midpoint of BC. If the area of DeltaABC is 96, the area of DeltaAEF is

In triangle ABC,D is the midpoint of BC and AD is perpendicular to AC. Then cos A.cos C=

In triangleABC , AD is a median . E is the midpoint of AD and F is the midpoint of AE. Prove that ar(ABF)= 1/8 ar(ABC).

The area of Delta ABC is 44 cm^(2) . If D is the midpoint of BC and E is the midpoint of AB, then the area ( in cm^2 ) of DeltaBDE is :

In Delta ABC, D and E are the midpoint of AB and AC respectively. Find the ratio of the areas of Delta ADE and Delta ABC .

ABC is a triangle in which D is the midpoint of BC and E is the midpoint of AD. Prove that ar(triangleBED)=(1)/(4)ar(triangleABC) .