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(1)/(2)mv^(2)=mgh जहाँ m द्रव्यमान v वेग...

`(1)/(2)mv^(2)=mgh` जहाँ m द्रव्यमान v वेग, g गुरुत्वीय त्वरण तथा h ऊँचाई है|

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Calculate the frequency of paritcle wave, when the kinetic energy of a sub-atomic particle is 3.79 xx 10^(-27) J . Hint : KE = (1)/(2) mv^(2) lambda = (h)/(mv) , lambda = ( v)/( v) :. (v)/(v) = (h)/( mv), v= (mv^(2))/( h) = ( 2 xx ( 1)/(2) mv^(2))/( h)