A solution is prepared by dissolving 10g of non-volatile solute in 200g of water. It has a vapour pressure of 31.84 mm Hg at 308 K. Calculate the molar mass of the solute. (Vapour pressure of pure water at 308K =32 mm Hg)

A solutions is prepared by dissolving 394 g of a nonvolatile solute in 622 g of water. The vapour pressure of solution is found to be 30.74 mm Hg at 30^@C . If vapour pressure of water at 30^@C is 31.8mm Hg, what is the molar mass of solute?

A solution is made by dissolving 30 g of a non-volatile solute in 90 g of water. It has a vapour pressure of 2.8 k Pa at 298 K. At 298 K, vapour pressure of pure water is 3.64 kPa. Calculate the molar mass of the solute.

A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further, 18 g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K. Calculate: vapour pressure of water at 298 K.

A solution containing 30g of non-volatile solute exactly in 90g of water has a vapour pressure of 2.8 kPa at 298 K. Further, 18 g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K. Calculate: molar mass of the solute

The vapour pressure of a solution containing 2 moles of a solute in 2 moles of water (vapour pressure of pure water = 24 mm Hg) is

The vapour pressure of a 5% aqueous solution of a non-volatile organic substances at 373K is 745 mm. calculate the molar mass of the solute. (Vapour pressure of water at 373K=760mm Hg).

The vapour pressure of a solution containing 13xx10^(-3) kg of solute in 0.1 kg of water at 298 K is 27.371 mm Hg. Calculate the molar mass of the solute. given that the vapour pressure of water at 298k is 28.065 mm hg