If `(x_1,y_1)` and `(x_2,y_2)` are the solution of the system of equation `log_225(x) + log_64(y) = 4` and `log_x (225)- log_y (64)= 1`, then show that the value of ` log_30 (x_1y_1x_2y_2) = 12`

If (x_1, y_1)&(x_2, y_2) are the solutions of the equaltions, (log)_(225)(x)+log_(64)(y)=4a n d(log)_x(225)-(log)_y(64)=1, (log)_(225)x_1dot(log)_(225)x_2=4 b. (log)_(225)x_1+(log)_(225)x_2=6 c. |(log)_(64)y_1-(log)_(64)y_2|=2sqrt(5) d. (log)_(30)(x_1x_2y_1y_2)=12

If (x_1, y_1)&(x_2, y_2) are the solutions of the equaltions, (log)_(225)(x)+log_(64)(y)=4a n d(log)_x(225)-(log)_y(64)=1, (A) (log)_(225)x_1dot(log)_(225)x_2=4 (B). (log)_(225)x_1+(log)_(225)x_2=6 (C). |(log)_(64)y_1-(log)_(64)y_2|=2sqrt(5) (D). (log)_(30)(x_1x_2y_1y_2)=12

Comprehension (Q. No. 6 to Q. No. 8) Let (x_1, y_1)&(x_2, y_2) are the solutions of the equation, (log)_(225)(x)+(log)_(64)(y)=4 and (log)_x(225)-(log)_y(64)=1 (log)_(225)x_1dot(log)_(225)x_2= 2 (b) 4 (c) 6 (d) 8

Comprehension (Q. No. 6 to Q. No. 8) Let (x_1, y_1)&(x_2, y_2) are the solutions of the equation, (log)_(225)(x)+(log)_(64)(y)=4 and (log)_x(225)-(log)_y(64)=1 (log)_(225)x_1dot(log)_(225)x_2= 2 (b) 4 (c) 6 (d) 8

If the solutions to the systom of equations given by log_(4095)x+log_(2015)y=2 and log_(x)4096-log_(2)2013=1are(x_(1)y_(1)) and (x_(1),y_(2)) then the value of log_(4)(x_(1)y_(1)x_(2)y_(2)) is

If (x_(1),y_(1))&(x_(2),y_(2)) are the solutions of the equaltions,log_(225)(x)+log_(64)(y)=4 and log_(x)(225)-log_(y)(64)=1log_(225)x_(1).log_(225)x_(2)=4 b.log_(225)x_(1)+log_(225)x_(2)=6c|log_(64)y_(1)-log_(64)y_(2)|=2sqrt(5)d*log_(30)(x_(1)x_(2)y_(1)y_(2))=12

The solutions to the system of equations log_(5)x+log_(27)y=4 and log_(x)5-log_(y)(27)=1 are (x_(1),y_(1)) and (x_(2),y_(2)) then log_(15)(x_(1)x_(2)y_(1)y2) is

Solve the system of equations log_2y=log_4(xy-2),log_9x^2+log_3(x-y)=1 .

Solve the system of equations log_2y=log_4(xy-2),log_9x^2+log_3(x-y)=1 .

Solve the system of equations log_2y=log_4(xy-2),log_9x^2+log_3(x-y)=1 .