`int dx/(sqrt2 ax-x^2)=a^n sin^-1{(x-a)/a}` a-> constant Find the value of n.

In the equation int (dx)/sqrt(2ax - x^(2) ) = a^(2) sin ^(-1) [(x)/(a) - 1] . Find the value of n .

Given that int (dx)/(sqrt(2 ax - x^2)) = a^n sin^(-1) ((x-a)/(a)) where a is a constant. Using dimensional analysis. The value of n is

Given that int (dx)/(sqrt(2 ax - x^2)) = a^n sin^(-1) ((x-a)/(a)) where a is a constant. Using dimensional analysis. The value of n is

int(dx)/(x sqrt(x^(2n)-a^(2n)))

where c is the constant of integration and m,n in N ,the find the valuc of (m+n). If int(dx)/(1+sqrt(x+1)+sqrt(x))=ax+b sqrt(x)+c int sqrt((x+1)/(x))dx where a,b,care constant,then find the value of (a+b+c)