Work done by 0.1 mole of a gas at `27^(@)C` to double its volume at constant pressure is `(R=2" cal mol"^(-1).^(@)K^(-1))`

Calculate the work done by 0.1 mole of a gas at 27^(@)C to double its volume at constant pressure (R = 2 cal mol^(-1)K^(-1))

Calculate the work done by 0.1 mole of a gas at 27^(@)C to double its volume at constant pressure (R = 2 cal mol^(-1)K^(-1))

Work done by 0.1 mole of a gas at 27°C to double its volume at constant pressure is (R = 2 cal/mol/K)

Work done by 0.1 mole of a gas at 27^@ C to double its volume at constant pressure is (use R=2 cal/mol ""^(@) C)

Work done by 0.1 mole of gas at 27^(@)C when it expands to double its volme at constant pressure is (assume R = 2 cal//mol-K )

What is the work done by 0.2 mole of a gas at room temperature to double its volume during isobaric process? (Take R=2 cal mol^(-1).^(@)C^(-1) )

What is the work done by 0.2 mole of a gas at room temperature to double its volume during isobaric process? (Take R=2 cal mol^(-1).^(@)C^(-1) )

0.1 moles of diatomic gas at 27^(@)C is heated at constant pressure, so that the volume is doubled. If R=2cal.mol^(-1)k^(-1) , the work done is

0.5 mole of diatomic gas at 27^(@)C is heated at constant pressure so that its tripled. If =8.3J "mole"^(-1)k^(-1) then work done is