A block of mass 2 kg, slides down a rough inclined plane of length I rn and inclination 60°. The coefficient ofkinetic friction is 0.4. What is the work done against friction, when it slides from the top to the bottom?

A block of mass 1 kg slides down on a rough inclined plane of inclination 60^(@) starting from its top. If the coefficient of kinetic friction is 0.5 and length of the plane is 1 m , then work done against friction is (Take g=9.8m//s^(2) )

A body weighing 20 kg just slides down a rough inclined plane that rises 5 in 12. The coefficient of friction is

A block of mass 1 kg slides down a rough inclined plane of inclination 60^(@) starting from its top. If coefficient of kinetic is 0.5 and length of the plane d=2 m, then work done against friction is

A block of mass 1 kg slides down a rough inclined plane of inclination 60^(@) starting from its top. If coefficient of kinetic is 0.5 and length of the plane d=2 m, then work done against friction is

When a body of mass M slides down an inclined plane of inclination theta , having coefficient of friction mu through a distance s, the work done against friction is :

When a body of mass M slides down an inclined plane of inclination theta , having coefficient of friction mu through a distance s, the work done against friction is :

A block of mass 2 kg slides down an incline plane of inclination 30°. The coefficient of friction between block and plane is 0.5. The contact force between block and plank is :

A block of mass 2 kg slides down an incline plane of inclination 30°. The coefficient of friction between block and plane is 0.5. The contact force between block and plank is :

A block of mass 5 kg slides down a rough inclined surface. The angle of inclination is 45^(@) . The coefficient of sliding friction is 0.20. When the block slides 10 cm, the work done on the block by force of friction is