" The function "f(x)=x^(2)-ax+3," if "'x'" is rational "=2-x," if "'x'" is irrational,is continuous at exactly two points then the possible values of 'a' are "

if f(x)=x^2-ax+3 , x is rational and f(x)=2-x , x is irrational is continuous at exactly two points, then the possible values of a

f(x)=1 for x is rational -1 for x is irrational,f is continuous on

f(x)=1 for x is rational f(x)=-1 for x irrational, f is continuous on

Find the value of x where f(x)={x ,if x is rational 1-x ,if x is irrational is continuous dot

If f(x)={x^(2) if x is rational and 0, if x is irrational }, then

Let f(x) = [{:(x^(2), " if x is irrational"),(1, " if x is rational"):} , then

Show that the function f defined by f(x)={(x if "x is rational"),(-x if "x is irrational"):} is continuous at x=0 AAxne0inR

A function f(x) is defind as f(x)={{:(x^(2)+ax+1, " x is rational "),(ax^(2)+2x+b,"x is irrational "):} is continuous at x=1and 3 , them find the values of a and b.