The emf of a cell corresponding to the reaction
`Zn +2H^(+)(aq) rarr Zn^(2+) (0.1M) +H_(2)(g) 1` atm is `0.28` volt at `25^(@)C`. Calculate the `pH` of the solution at the hydrogen electrode.
`E_(Zn^(2+)//Zn)^(@) =- 0.76` volt and `E_(H^(+)//H_(2))^(@) = 0`

The emf of a cell corresponding to the reaction. Zn(s)+ 2H^(+)(aq)rightarrow Zn^(2+)(0.1M)+H_(2) (g,1atm) is 0.28 V at 25^(@) C . Calculate pH of the solution.

The emf of a cell corresponding to the reaction, Zn(s) + 2H^(+) ( aq) rarr Zn^(2+) ( 0.1 M ) + H_(2) ( g , 1 atm) is 0.28 V at 25^(@)C . Write the half-cell reaction and calculate the pH of the solution at the hydrogen electrode. E_(Zn^(2+)//Zn)^(@) = - 0.76V, E_(H^(+) //H_(2))^(@) = 0

Emf of a cell corresponding to the reaction:- Zn(s) +2H^(+) (aq) rarr Zn^(2+)(aq) [0.1M] +H_(2)(g) [1.0atm] is 0.49V at 25^(@)C, E_(Zn^(2+)//Zn)^(@) = - 0.76 V . The pH of solution in cathode chamber is.

Emf of a cell corresponding to the reaction:- Zn(s) +2H^(+) (aq) rarr Zn^(2+)(aq) [0.1M] +H_(2)(g) [1.0atm] is 0.49V at 25^(@)C, E_(Zn^(2+)//Zn)^(@) = - 0.76 V . The pH of solution in cathode chamber is.

Emf of a cell corresponding to the reaction:- Zn(s) +2H^(+) (aq) rarr Zn^(2+)(aq) [0.1M] +H_(2)(g) [1.0atm] is 0.49V at 25^(@)C, E_(Zn^(2+)//Zn)^(@) = - 0.76 V . The pH of solution in cathode chamber is.

The emf of a cell corresponding to the following reaction is 0.0199 V at 298 K. Zn(s) + 2H^(+)(aq) rightarrow Zn^(2+)(0.1M) + H_(2)(g)(E_(Zn//Zn^(2+))^(@) = 0.76V The approximate pH of the solution at the electrode where hydrogen is being produced is [pH_(2) = 1 atm] :

Zn(s)+2H^(+)(aq)rarr Zn^(2+)(0.1M)+H_(2)(g,"1 atm") Cell potential of a chemical cell in which the above reaction occurs is +0.28V at 25^(@)C . Write the half-cell reactions and calculate the pH of the hydrogen electrode. Give : E_("Zn^(2+)|Zn)^(@)=-0.76V and E_(2H^(+)|H_(2))^(@)=0.00V .

Zn(s)+2H^(+)(aq)rarr Zn^(2+)(0.1M)+H_(2)(g,"1 atm") Cell potential of a chemical cell in which the above reaction occurs is +0.28V at 25^(@)C . Write the half-cell reactions and calculate the pH of the hydrogen electrode. Give : E_("Zn^(2+)||Zn)^(@)=-0.76V and E_(2H^(+)||H)^(@)=0.00V