An electric kettle of `1200W`has 1 kg water at `20^@C`. The water equivalent of the kettle is `500g`. The time required to heat water from `20^(@) to 100^(@)C` will be (specific heat of water = `4200 J//kg^(@)C)`.

A 210 W heater is used to heat 100 g water. The time required to raise the temperature of this water from 25^(@)C to 100^(@)C is (specific heat capacity of water =4200" J/Kg-"^(@)C )

An electric kettle of 2000 Wis used to boil 20 litres of water. Find the time required to boil to the water from its initial temperature of 20^(@)C . (Take specific heat of water as 4200 J kg^(-1) K^(-1) . Density of water = 1000kg m^(-3) )

Find the increase in mass when 1 kg of water is heated from 0^@C to 100^@C . Specific heat capacity of water = 4200 J kg^(-1) K^(-1) .

Find the increase in mass when 1 kg of water is heated from 0^@C to 100^@C . Specific heat capacity of water = 4200 J kg^(-1) K^(-1) .

Calculate the heat energy required to raise the temperature of 2 kg of water from 10^@ C to 50^@ C. Specific heat capacity of water is 4200 J kg^(-1) K^(-1) .

Calculate the heat energy required to raise the temperature of 2 kg of water from 10^@C to 50^@C . Specific heat capacity of water is 4200 JKg^(-1) K^(-1)

Find the heat energy required to raise the temperature of 5 kg of water at 80^@C to 100^@C . (Specific heat of water is 1 cal g^(-1)""^(@)C^(-1) )