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If 1/6sintheta,costheta,tantheta are in ...

If `1/6sintheta,costheta,tantheta` are in `GdotPdot,` then `theta` is equal to `(n in Z)` `2npi+-pi/3` (b) `2npi+-pi/6` `npi+(-1)^npi/3` (d) `npi+pi/3`

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