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cos 40^0+cos 80^0+cos 160^0+cos 240^0= ...

`cos 40^0+cos 80^0+cos 160^0+cos 240^0=` `0` b. `1` c. `1//2` d. `-1//2`

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cos 40^0+cos 80^0+cos 160^0+cos 240^0= a. 0 b. 1 c. 1//2 d. -1//2

cos40 + cos80 + cos160 + cos240

Prove that: cos 80^0+cos 40^0-cos 20^0=0

Prove that: cos 80^0+cos 40^0-cos 20^0=0

Prove that: cos 80^0+cos 40^0-cos 20^0=0

(2cos 40^0-cos 20^0)/(sin 20^0)=

cos40^(@)+cos 80^(@)+cos160^(@)+cos240^(@) =

Prove that : cos 20^0cos 40^0cos 60^0cos 80^0=1/(16)

Prove that: \ cos 20^0cos 40^0cos 80^0=1/8

Prove that: cos40^0cos80^0cos 160^0=\ -1/8