int_(0)^( pi/2)(root(3)(sin x))/(root(3)(sin x)+root(3)(cos x))dx=a*(pi)/(2)," then value of a is "

int_(0)^( pi/2)cos^(3)x root(4)(sin x)dx

int_(0)^(pi//2)(root3tanx)/((root3tanx+root3cotx))dx=?

int_0^(pi//2) (3^(sin x))/(3^(sin x) + 3^(cos x)) dx equals :

int_(pi/6)^(pi/3) (sin x+ cos x)/(sqrt(sin 2x))dx

int_(pi/6)^(pi/3) (sin x+ cos x)/(sqrt(sin 2x))dx

"integral "I=int_(0)^(2 alpha)(root(4)(sin(3 alpha-x)))/(root(4)(sin(3 alpha-x))+root(4)(sin(alpha+x)))dx" is "

Evaluate : int_(0)^(pi//2) (3^("cos x"))/(3^("sin x") + 3^("cos x")) dx

int_0^(pi/2) (sin^(3)x)/(cos^(3)x+sin^(3)x) dx =

Evaluate: int(dx)/(root(3)(sin^(11)x cos x))

Evaluate the following : int_(0)^(pi//2)(root3(secx))/(root3(secx)+root3("cosec x"))dx