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[" Q.39Calculate molality "(m)" of each ...

[" Q.39Calculate molality "(m)" of each ion present in the aqueous solution of "2MNH_(4)Cl" assuming "100%],[" dissociation according to reaction."],[qquad [NH_(4)Cl(aq)longrightarrow NH_(4)^(+)(aq)+Cl^(-)(aq)],[" Given : Density of solution "=3.107gm/ml.]]

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Calculate molality (m) of each ion present in the aqueous solution of 2M NH_(4)Cl assuming 100% dissociation according to reaction NH_(4) Cl (aq) rarr NH_(4)^(+) (aq) + Cl^(-) (aq) Given: Density of solution = 3.107 gm/ml

Calculate molality (m) of each ion present in the aqueous solution of 2M NH_(4)Cl assuming 100% dissociation according to reaction NH_(4) Cl (aq) rarr NH_(4)^(+) (aq) + Cl^(-) (aq) Given: Density of solution = 3.107 gm/ml

Why is an aqueous solution of NH_4Cl acidic ?

Aqueous solution of NH_(4)Cl is acidic. Explain.

An aqueous solution of NH_(4)Cl is acidic. Give reason.

Aqueous solution of NH_(4)Cl is …… in nature due to behaviour of….ion in solution:

Aqueous solution of NH_(4)Cl is …… in nature due to behaviour of….ion in solution: