" EN of the element (A) is "E(1)" and "|...

" EN of the element (A) is "E_(1)" and "|P" is "E_(2)" .Hence according to mulliken scale EAwill be: "

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EN of the element (A) is E_1 and IP is E_2 . Hence EA will be

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EN of the element (A) is E_(1) and EA is E_(2) hence IP will be :

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The ionisation potential and electron affinity of an element "X" are 275 and 86 kcal/mole. Then the electronegativity of "X" according to Mulliken scale is

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एक सम पाँसे को उछाला गया है | घटनाओ E(1)={1,3,5},E(2)={2,3},E(3)={2,3,...
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