[" The horizontal range of a projectiles is "R" and the maximum helight attained by it is "1" .A strong wind now begins to blow in the direction of motion "],[" the projectile,giving it a constant horizontal acceleration "=8/2" .Under the same conditions of projection,the horkontal rang" of the projectile mithe "]

The horizontal range of a projectile is R and the maximum height attained by it is H. A strong wind now begins to below in the direction of motion of the projectile, giving it a constant horizontal acceleration =g//2 . Under the same conditions of projection. Find the horizontal range of the projectile.

The horizontal range of a projectile is R and the maximum height attained by it is H. A strong wind now begins to below in the direction of motion of the projectile, giving it a constant horizontal acceleration =g//2 . Under the same conditions of projection. Find the horizontal range of the projectile.

The horizontal range of a projectile is R and the maximum height attained by it is H. A strong wind now begins to below in the direction of motion of the projectile, giving it a constant horizontal acceleration =g//2 . Under the same conditions of projection. Find the horizontal range of the projectile.

The horizontal range of a projectile is R and the maximum height at tained by it is H. A strong windnow begins to blow in the direction of the motion of the projectile, giving it a constant horizontal acceleration = g/2. Under the same conditions of projection, the horizontal range of the projectile will now be:

The horizontal range of a projectile is R and the maximum height attained by it is H. A strong wind now beings to blow in the direction of horizontal motion of projectile, giving to constant horizontal acceleration equal to g. Under the same conditions of projections , the new range will be (g = acceleration due to gravity)

The horizontal range of a projectile is R and the maximum height attained by it is H. A strong wind now beings to blow in the direction of horizontal motion of projectile, giving to constant horizontal acceleration equal to g. Under the same conditions of projections , the new range will be (g = acceleration due to gravity)

The maximum horizontal range of a projectile is 400 m . The maximum value of height attained by it will be

If the horizontal range of a projectile be a and the maximum height attained by it is b, then prove that the velocity of projection is