Elements `A, B, C, D` and `E` have the following electronic configurations:
A: `1s^(2) 2s^(2) 2p^(1)`
B: `1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(1)`
C: `1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(2)`
D: `1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(5)`
E: `1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2)`
Which among these will belong to the same group in the periodic table?

Options

A. A and D
B. C and D
C. A and B
D. A and D

Answer

C

Explanation

The elements having similar valence electronic configuration belong to same group of the periodic table. Therefore, A and B having 3 electrons in the valence shell belong to same group.