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Explain why N(2) has a greater bond diss...

Explain why `N_(2)` has a greater bond dissociation energy than `N_(2)^(+)` while `O_(2)` has lesser bond dissociation energy than `O_(2)^(+).`

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The M.O. electronic configurations are :
`N_(2):KK(sigma2s)^(2)(sigma^(**)2s)^(2)(pi2p_(x))^(2)(pi2p_(y))^(2)(sigma2p_(z))^(2)`
`"Bond order"=(8-2)/(2)=3`
`N_(2)^(+):KK(sigma2s)^(2)(sigma^(**)2s)^(2)(pi2_(x))^(2)(pi2p_(y))^(2)(sigma2p_(x))^(1)`
`"Bond order"=(7-2)/(2)=2(1)/(2)`
Since bond order of `N_(2)` is larger than that of `N_(2)^(+), N_(2)` has greater bond dissociation energy than `N_(2)^(+)`.
`O_(2):KK(sigma2s)^(2)(sigma^(**)2s)^(2)(sigma2p_(x))^(2)(pi2p_(x))^(2)(pi2p_(y))^(2)(pi^(**)2p_(x))^(2),(pi^(**)2p_(y))^(1)`
`"Bond order : "(8-4)/(2)=2`
`O_(2)^(+):KK(sigma2s)^(2)(sigma^(**)2s)^(2)(sigma2p_(z))^(2)(pi2p_(x))^(2)(pi2p_(x))^(2)(pi2p_(x))^(2)(pi2p_(y))^(2)(pi^(**)2p_(x))^(1)`
`"Bond order"=(8-3)/(2)=2(1)/(2)`
Since bond order of `O_(2)` is less than that of `O_(2)^(+), O_(2)`
has lower bond dissociation energy than `O_(2)^(+).`
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