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Describe hybridisation in the case of PC...

Describe hybridisation in the case of `PCl_(5) and SF_(5)` The axial bonds are longer as compared to rwuatorial bonds in `PCl_(5)` whereas in `SF_(6)` both axial bonds and equatorial bonds and have the same bond length. Explain.

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Describe hybridisation in the case of PCl_(5) and SF_(6) The axial bonds are longer as compared to equatorial bonds in PCl_(5) whereas in SF_(6) both axial bonds and equatorial bonds and have the same bond length. Explain.

Describe the hybridisation in case of PCl_(2). Why are the axial bonds longer as compared to equatorial bonds ?

Describe the hydribisation in case of PCl_(5) . Why are the axial bonds longer as compared to equatorial bonds?

Number of right angle bonds in PCl_(5) is _______.

How many equitorial bonds are there are in PCl_(5) ?

Explain the structure of PCl_(5) according to hybridization. Why all P – Cl bonds lengths are not equivalent in PCl_(5) ?

Explain the structure of PCl_(5) according to hybridization. Why all P – Cl bonds lengths are not equivalent in PCl_(5) ?

Assertion : In trigonal bipyramidal structure two axial bonds are longer than the equatorial bonds. Reason : Axial bonds suffer more repulsion as compared to equatorial bonds.