Hybridisation helps us to understand the geometry of the molecules. This is because hybridised orbitals are directed in space in some preferred directions to have stable arrangement, which determine the geometry. The common hybridisation are sp (linear), `sp^(2)` (trigonal planar), `sp^(3)` (tetrahedral), `sp^(3)d` (trigona bipyramidal), `sp^(3)d^(2)` (octahedral) and `sp^(3)d^(3)` (pentagonal bipyramidal). The presence of lone pairs in addition to bond pairs distort the geometry because `"lone pair "-" lone pair repulsion"gt" lone pair "-" bond repulsion" gt" bond pair" -"bond pair repulsion"`.
Which d - orbitals are involved in `sp^(3)d^(2)` hybridisation in `SF_(6)` molecule?

Explanation

To determine which d-orbitals are involved in the `sp^(3)d^(2)` hybridization of the `SF_(6)` molecule, we can follow these steps:

### Step 1: Identify the Hybridization
The hybridization of `SF_(6)` is given as `sp^(3)d^(2)`. This indicates that the molecule uses one s orbital, three p orbitals, and two d orbitals to form hybrid orbitals.

### Step 2: Determine the Geometry
The geometry of `SF_(6)` is octahedral. In an octahedral arrangement, there are six bonding pairs of electrons around the central sulfur atom, and no lone pairs.

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