The bond order in `O_(2)^(+)` is ……………….tahn in `O_(2)`.

Explanation

To determine the bond order in \( O_2^+ \) compared to \( O_2 \), we will follow these steps:

### Step 1: Determine the Electron Configuration of \( O_2 \)
Oxygen has an atomic number of 8, so \( O_2 \) has a total of 16 electrons (8 from each oxygen atom). The molecular orbital configuration for \( O_2 \) is as follows:
- \( \sigma_{1s}^2 \)
- \( \sigma^*_{1s}^2 \)
- \( \sigma_{2s}^2 \)
- \( \sigma^*_{2s}^2 \)
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