Total number of coordinate bonds present in `CuSO_(4).5H_(2)O` is

Explanation

To determine the total number of coordinate bonds present in \( \text{CuSO}_4 \cdot 5\text{H}_2\text{O} \) (copper sulfate pentahydrate), we will analyze the structure and bonding of the compound step by step.

### Step-by-Step Solution:

1. **Identify the Components of the Compound**:
- The compound consists of copper sulfate (\( \text{CuSO}_4 \)) and five water molecules (\( 5\text{H}_2\text{O} \)).
- Copper in copper sulfate is in the +2 oxidation state.

2. **Understanding Coordinate Bonds**:
- A coordinate bond (or dative bond) is formed when one atom donates both electrons to form a bond with another atom.
- In this case, water molecules can act as Lewis bases, donating a lone pair of electrons to the copper ion.

3. **Analyzing the Copper Ion**:
- The copper ion (\( \text{Cu}^{2+} \)) can accept electron pairs from the water molecules.
- Each water molecule has two lone pairs of electrons on the oxygen atom.

4. **Formation of Coordinate Bonds**:
- In \( \text{CuSO}_4 \cdot 5\text{H}_2\text{O} \), the copper ion forms coordinate bonds with the oxygen atoms of the water molecules.
- Since there are five water molecules, each donating one pair of electrons to the copper ion, this results in five coordinate bonds.

5. **Conclusion**:
- The total number of coordinate bonds present in \( \text{CuSO}_4 \cdot 5\text{H}_2\text{O} \) is **5**.

### Final Answer:
The total number of coordinate bonds present in \( \text{CuSO}_4 \cdot 5\text{H}_2\text{O} \) is **5**.