The number of molecules having more than one lone pair among the following :
`XeF_(4), ClF_(3), NH_(3), SF_(4), XeF_(2), BrF_(5), H_(2)O`

Explanation

To determine the number of molecules from the list that have more than one lone pair, we will analyze each molecule one by one, calculating the number of lone pairs based on the valence electrons of the central atom and the bonding pairs with surrounding atoms.

### Step-by-Step Solution:

1. **XeF₄ (Xenon Tetrafluoride)**:
- Valence electrons of Xenon (Xe) = 8 (noble gas)
- Valence electrons from 4 Fluorine (F) = 4
- Total = 8 + 4 = 12
- Hybridization = Total valence electrons / 2 = 12 / 2 = 6 (SP³d²)
- Bond pairs = 4 (with 4 Fluorine atoms)
- Lone pairs = Total pairs - Bond pairs = 6 - 4 = 2
- **Lone pairs: 2** (more than one)

2. **ClF₃ (Chlorine Trifluoride)**:
- Valence electrons of Chlorine (Cl) = 7
- Valence electrons from 3 Fluorine (F) = 3
- Total = 7 + 3 = 10
- Hybridization = 10 / 2 = 5 (SP³d)
- Bond pairs = 3 (with 3 Fluorine atoms)
- Lone pairs = 5 - 3 = 2
- **Lone pairs: 2** (more than one)

3. **NH₃ (Ammonia)**:
- Valence electrons of Nitrogen (N) = 5
- Valence electrons from 3 Hydrogen (H) = 3
- Total = 5 + 3 = 8
- Hybridization = 8 / 2 = 4 (SP³)
- Bond pairs = 3 (with 3 Hydrogen atoms)
- Lone pairs = 4 - 3 = 1
- **Lone pairs: 1** (not more than one)

4. **SF₄ (Sulfur Tetrafluoride)**:
- Valence electrons of Sulfur (S) = 6
- Valence electrons from 4 Fluorine (F) = 4
- Total = 6 + 4 = 10
- Hybridization = 10 / 2 = 5 (SP³d)
- Bond pairs = 4 (with 4 Fluorine atoms)
- Lone pairs = 5 - 4 = 1
- **Lone pairs: 1** (not more than one)

5. **XeF₂ (Xenon Difluoride)**:
- Valence electrons of Xenon (Xe) = 8
- Valence electrons from 2 Fluorine (F) = 2
- Total = 8 + 2 = 10
- Hybridization = 10 / 2 = 5 (SP³d)
- Bond pairs = 2 (with 2 Fluorine atoms)
- Lone pairs = 5 - 2 = 3
- **Lone pairs: 3** (more than one)

6. **BrF₅ (Bromine Pentafluoride)**:
- Valence electrons of Bromine (Br) = 7
- Valence electrons from 5 Fluorine (F) = 5
- Total = 7 + 5 = 12
- Hybridization = 12 / 2 = 6 (SP³d²)
- Bond pairs = 5 (with 5 Fluorine atoms)
- Lone pairs = 6 - 5 = 1
- **Lone pairs: 1** (not more than one)

7. **H₂O (Water)**:
- Valence electrons of Oxygen (O) = 6
- Valence electrons from 2 Hydrogen (H) = 2
- Total = 6 + 2 = 8
- Hybridization = 8 / 2 = 4 (SP³)
- Bond pairs = 2 (with 2 Hydrogen atoms)
- Lone pairs = 4 - 2 = 2
- **Lone pairs: 2** (more than one)

### Summary of Findings:
- Molecules with more than one lone pair:
- XeF₄: 2 lone pairs
- ClF₃: 2 lone pairs
- XeF₂: 3 lone pairs
- H₂O: 2 lone pairs

### Total Count:
- Total number of molecules with more than one lone pair = 4 (XeF₄, ClF₃, XeF₂, H₂O)

### Final Answer:
**The number of molecules having more than one lone pair is 4.**

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