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What is K(c ) for the following equilibr...

What is `K_(c )` for the following equilibrium concentration of each substance is:
`[SO_(2)]=0.60 M, [O_(2)]=0.82 M` and `[SO_(3)]=1.90 M`?

`2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g)`

Text Solution

Verified by Experts

The equilibrium constant `K_c` is :
`K_c=([SO_3]^2)/([SO_2]^2[O_2])`
`[SO_2]`=0.60 M, `[O_2]`=0.82 M and `[SO_3]` = 1.90 M
`K_c=(1.90M)^2/((0.60M)^2(0.82M))`
`=12.229 M^(-1)` or `12.229 mol^(-1)L`
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