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PCl(5), PCl(3) and Cl(2) are at equilibr...

`PCl_(5), PCl_(3)` and `Cl_(2)` are at equilibrium at `500 K` and having concentration `1.59 M PCl_(3), 1.59 M Cl_(2)` and `1.41 M PCl_(5)`. Calculate `K_(c)` for the reaction,
`PCl_(5) hArr PCl_(3) + Cl_(2)`

Text Solution

Verified by Experts

The correct Answer is:
1.7
The equilibrium constant for the reaction may be written as :
`K_c=([PCl_3][Cl_2])/([PCl_5])`
`[PCl_5]` = 1.41 M , `[PCl_3]` =1.59 M , `[Cl_2]` =1.59 M
`=((1.59)(1.59))/1.41`
=1.79 M
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