Home
Class 11
CHEMISTRY
Hydrolysis of sucrose gives <center>"S...

Hydrolysis of sucrose gives
`"Sucrose" +H_(2)OhArr"Glucose + Fructose"`

Equilibrium constant `K_(c)` for the reaction is `2xx10^(13)` at `300 K`. Calculate `DeltaG^(ɵ)` at `300 K`.

Text Solution

Verified by Experts

`DeltaG^@`=`-2.303 RT log K`
`K=2xx10^13 , T=300 K, R= 8.314 "J mol"^(-1) K^(-1)`
`therefore DeltaG^@=-2.303xx(8.314 "J mol"^(-1)K^(-1))xx(300K)xxlog 2 xx10^13`
`=-7.64xx10^4 "J mol"^(-1)`
`=-76.4 "kJ mol"^(-1)`
Promotional Banner

Topper's Solved these Questions

  • EQUILIBRIUM

    MODERN PUBLICATION|Exercise Practice Problems|114 Videos
  • EQUILIBRIUM

    MODERN PUBLICATION|Exercise Conceptual Question 1|24 Videos
  • ENVIRONMENTAL POLLUTION

    MODERN PUBLICATION|Exercise UNIT PRACTICE TEST|15 Videos
  • HALOALKANES AND HALOARENES

    MODERN PUBLICATION|Exercise UNIT PRACTICE TEST|12 Videos

Similar Questions

Explore conceptually related problems

Hydrolysis of sucrose is given by the following reaction. Sucrose+ H_2O rarr Glucose + Fructose If the equilibrium constant (K_c) is 2xx10^13 at 300 K the value of delta_r G^theta at the same temperature will be:

What will be the value of Delta G .If equilibrium constant for a reaction is 10 at 300K

The equilibrium constant for a reaction is 100 what will be the value of DeltaG^(@) ? R=8.314JK^(-1)mol^(-1),T=300 K :-

The equilibrium constant of a reaction is 1xx10^(20) at 300 K . The standard free energy change for this reaction is :

The equilibrium constant for a reaction is 10 . What will be the value of DeltaG^(Θ) ? R=8.314 J K^(-1) mol^(-1), T=300 K .