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The value of DeltaG^(ɵ) for the phosphor...

The value of `DeltaG^(ɵ)` for the phosphorylation of glycose in glycolysis is `13.8 kJ mol^(-1)`. Find the value of `K_(c)` at `298 K`

Text Solution

Verified by Experts

`DeltaG^@=13.8 kJ mol^(-1)=13.8 xx10^3 Jmol^(-1)`
`DeltaG^@` =-2.303 RT log K
or log K=`-(DeltaG^@)/(2.303RT)`
`=-(13.8xx10^3)/(2.303xx8.314xx298)`
=-2.418
`K=3.82xx10^(-3)`
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