The `pH` of a `0.1` M solution of `NH_4Cl` is `5.127`. Calculate (i) the degree of hydrolysis (ii) the hydrolysis constant and (iii) dissociation constant of the base.

Explanation

To solve the problem step by step, we will follow the outlined approach in the video transcript.

### Given:
- Concentration of \( NH_4Cl = 0.1 \, M \)
- pH of the solution = 5.127

### Step 1: Calculate \( [H^+] \)
The pH is given by the formula:
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