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A 0.02 M solution of pyridinium hydrochl...

A `0.02 M` solution of pyridinium hydrochloride has `pH=3.44`. Calculate the ionization constant of pyridine.

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pH of pyridinium hydrochloride = 3.44
Pyridinium hydrochoride is a salt of weak base and strong acid.pH of solution is given as:
`pH=1/2pK_w-1/2pK_b-1/2`log c
`3.44=1/2xx14-1/2pK_b-1/2log 0.02`
`3.44=7-1/2 pK_b-1/2xx(-1.698)`
`1/2pK_b` = 7+0.849-3.44
`1/2pK_b` = 4.409
`pK_b` =8.818
`-log K_b` = 8.818
`log K_b=-8.818 = bar(9).182`
`K_b=1.52xx10^(-9)` .
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