The solubility of `SrF_2` in water is `1.2 xx 10^(-2)g L^(-1)`. Calculate the solubility product of the salt at room temperature (molecular mass of `SrF_2` = 125.6).

Explanation

To calculate the solubility product (Ksp) of `SrF_2`, we can follow these steps:

### Step 1: Calculate the molar solubility of `SrF_2`
Given that the solubility of `SrF_2` in water is `1.2 x 10^(-2) g L^(-1)` and the molecular mass of `SrF_2` is `125.6 g/mol`, we can convert the solubility from grams per liter to moles per liter (mol/L).

\[ \text{Molar solubility} = \frac{\text{Solubility (g/L)}}{\text{Molar mass (g/mol)}} \]
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