Home
Class 11
CHEMISTRY
Calculate the solubility of barium sulp...

Calculate the solubility of barium sulphate when 0.05 M barium chloride solution added to it . `K_(sp)` of `BaSO_4 =1.1xx10^(-10)` .

Text Solution

AI Generated Solution

To calculate the solubility of barium sulfate (BaSO₄) when 0.05 M barium chloride (BaCl₂) is added, we can follow these steps: ### Step 1: Write the dissociation equation for BaSO₄ Barium sulfate dissociates in water as follows: \[ \text{BaSO}_4 (s) \rightleftharpoons \text{Ba}^{2+} (aq) + \text{SO}_4^{2-} (aq) \] ### Step 2: Define the solubility Let the solubility of BaSO₄ in the presence of 0.05 M BaCl₂ be \( S \). In this case, the concentration of barium ions from BaCl₂ will be 0.05 M. ...
Promotional Banner

Topper's Solved these Questions

  • EQUILIBRIUM

    MODERN PUBLICATION|Exercise Practice Problems|114 Videos
  • EQUILIBRIUM

    MODERN PUBLICATION|Exercise Conceptual Question 1|24 Videos
  • ENVIRONMENTAL POLLUTION

    MODERN PUBLICATION|Exercise UNIT PRACTICE TEST|15 Videos
  • HALOALKANES AND HALOARENES

    MODERN PUBLICATION|Exercise UNIT PRACTICE TEST|12 Videos

Similar Questions

Explore conceptually related problems

What will be the pH of 0.05 M barium hydroxide solution ?

Calculate the solubility of AgCN in a buffer solution of pH = 3 , Given K_(sp) of AgCN = 1.2 xx 10^(-16) and K_(a) for HCN = 4.8 xx 10^(-10) .

The solubility of BaSO_(4) in pure water (in g L^(-1) ) is closest to [Given: K_(sp)" for "BaSO_(4)" is " 1.0xx10^(-10)" at "25^(@)C . Molecular weight of BaSO_(4)" is "233g mol^(-1) ]

The insoluble product obtained when a solution of barium chloride is added to a solution of sodium sulphate is

The colour of the precipitate formed when barium chloride solution is mixed with sodium sulphate solution is

The solubility of AgCl in 0.1 M NaCl is ( K_(sp) of AgCl = 1.2 xx 10^(-10) )