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The solubility product of Al(OH)3 is 2.7...

The solubility product of `Al(OH)_3` is `2.7xx10^(-11)`. Calculate its solubility is `gL^(-1)` and also find out pH of this solution .

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To solve the problem, we will follow these steps: ### Step 1: Write the dissociation equation for Al(OH)₃ The dissociation of aluminum hydroxide can be represented as: \[ \text{Al(OH)}_3 (s) \rightleftharpoons \text{Al}^{3+} (aq) + 3 \text{OH}^- (aq) \] ...
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