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Equal volumes of 25.0 cm^3 of 5.0xx10^(-...

Equal volumes of 25.0 `cm^3` of `5.0xx10^(-2)M Ba(NO_3)_2` and `2xx10^(-2)` M NaF solution are mixed. Predict , whether precipitation of `BaF_2` will be formed or not (`K_"sp"` of `BaF_2=1.7xx10^(-6)` at 298 K).

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To determine whether precipitation of BaF₂ will occur when equal volumes of Ba(NO₃)₂ and NaF solutions are mixed, we can follow these steps: ### Step 1: Determine the concentrations after mixing We have two solutions: - Volume of Ba(NO₃)₂ = 25.0 cm³ (5.0 x 10⁻² M) - Volume of NaF = 25.0 cm³ (2.0 x 10⁻² M) When mixed, the total volume becomes: ...
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