Write the formula of conjugate acids of :
(i) `C_6H_5OH` , (ii) `NH_2NH_2` , (iii) `HCO_3^-`

Answer

To find the conjugate acids of the given compounds, we need to understand that a conjugate acid is formed when a base accepts a proton (H⁺). Below are the steps to determine the conjugate acids for each of the given compounds:

### Step 1: Identify the first compound, `C6H5OH` (Phenol).
- **Action**: Phenol can act as a weak base. When it accepts a proton (H⁺), it becomes `C6H5OH2⁺`.
- **Conjugate Acid**: The conjugate acid of phenol is `C6H5OH2⁺`.

### Step 2: Identify the second compound, `NH2NH2` (Hydrazine).
- **Action**: Hydrazine can also act as a base. When it accepts a proton (H⁺), it becomes `NH3NH3⁺` (or simply `NH3` with an additional proton).
- **Conjugate Acid**: The conjugate acid of hydrazine is `NH3NH3⁺`.

### Step 3: Identify the third compound, `HCO3⁻` (Bicarbonate).
- **Action**: Bicarbonate can act as a base as well. When it accepts a proton (H⁺), it becomes `H2CO3` (carbonic acid).
- **Conjugate Acid**: The conjugate acid of bicarbonate is `H2CO3`.

### Summary of Conjugate Acids:
1. For `C6H5OH`: Conjugate Acid = `C6H5OH2⁺`
2. For `NH2NH2`: Conjugate Acid = `NH3NH3⁺`
3. For `HCO3⁻`: Conjugate Acid = `H2CO3`

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