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If 0.561 g of (KOH) is dissolved in wate...

If `0.561 g` of `(KOH)` is dissolved in water to give. `200 mL` of solution at `298 K`. Calculate the concentration of potassium, hydrogen and hydroxyl ions. What is its `pH`?

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The correct Answer is:
`[K^+]=[OH^-]`=0.05, `[H^+]=2.0xx10^(-13)`M , pH=12.70
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