Calculate the percent hydrolysis of acetic acid in a solution 2.3 M in `CH_(3)COOH` and 0. 1 in HCl . `K_(a) = 1.8 xx10^(-5)`

Answer

`0.00745%`

Explanation

`h=sqrt(K_w/(K_a.c))`
`K_w=1.0xx10^(-14) , K_a=1.8xx10^(-5)` , c=0.1
`h=sqrt((1.0xx10^(-14))/(1.8xx10^(-5)xx0.1))`
`=7.45xx10^(-5)` or 0.00745%