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Why does the dissociation of PCl5 decrea...

Why does the dissociation of `PCl_5` decrease in the presence of `Cl_2` ?

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To understand why the dissociation of \( PCl_5 \) decreases in the presence of \( Cl_2 \), we can analyze the reaction and apply Le Chatelier's Principle step by step. ### Step 1: Write the dissociation reaction of \( PCl_5 \) The dissociation of phosphorus pentachloride (\( PCl_5 \)) can be represented by the following chemical equation: \[ PCl_5 (g) \rightleftharpoons PCl_3 (g) + Cl_2 (g) ...
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The degree of dissociation of PCl_(5)

Phosphorus pentachloride dissociates as follows in a closed reaction vessel. PCl_5(g) hArr PCl_3(g) +Cl_2(g) If total pressure at equilibrium of the reactions mixture is P and degree of dissociation of PCl_5 is x, the partial pressure of PCl_3 will be:

The degree of dissociation of PCl_(5) decreases with increase in pressure.

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MODERN PUBLICATION-EQUILIBRIUM-Conceptual Question 1
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  9. Why does the dissociation of PCl5 decrease in the presence of Cl2 ?

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  15. Which of the following reactions will get affected by increasing the p...

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  16. At 473 K, equilibrium constant K(c ) for decomposition of phosphorus p...

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